What Is the Tension T1 in the Cord Attaching the Baby to the Scale

January 11, 2022 Post a Comment

22. Consider the baby being weighed in Figure 4.34. (a) What is the mass of the child and basket if a scale reading of 55 N is observed? (b) What is the tension T1 in the cord attaching the baby to the scale? (c) What is the tension Tz in the cord attaching the scale to the ceiling; if the scale has a mass Of 0.500 kg? (d) Draw sketch of the situation indicating the system of interest used to solve each part: The masses of the cords are negligible.

22. Consider the baby being weighed in Figure 4.34. (a) What is the mass of the child and basket if a scale reading of 55 N is observed? (b) What is the tension T1 in the cord attaching the baby to the scale? (c) What is the tension Tz in the cord attaching the scale to the ceiling; if the scale has a mass Of 0.500 kg? (d) Draw sketch of the situation indicating the system of interest used to solve each part: The masses of the cords are negligible.

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Consider the baby being weighed in Figure 4.34 . (a) What is the mass of the child and basket if a scale reading of 55 $\mathrm{N}$ is observed? (b) What is the tension $T_{1}$ in the cord attaching the baby to the scale? (c) What is the tension $T_{2}$ in the cord attaching the scale to the ceiling, if the scale has amass of 0.500 kg? (d) Draw a sketch of the situation indicating the system of interest used to solve each part. The masses of the cords are negligible.

That a we need three mean the combined mass off the child in the basket if you're given the scale, reading is $55. So let's make on illustrated Short for the spread thickeners in Are you so you hear the seat? You have your the ceiling, There's a rule. Then there is this deal. There's another goal. And here's the Baskin Reda. Okay, so, baby here, off course eyes after upon the gravitational force, which is actually the week off the baby together with the basket. And then we have attention here, exerted by the room on the basket with the baby And then, of course, to say intention here, pulling down the scale and then the scale is being or the tension in the room putting this deal is that's label it subdued and then attention in the room. This part of pulling the ceiling is also equal to E. So So what is this word on industry, Sean Sin, Are you here? So as you can see, the baby in the basket experiences to forces before was Bruce on. Uh, that is why b b no basket. So the baby in the basket experiences forces so it's weight or in a gravitational force and then shown once with attention from the roof, attaching it to the scale. So as we know, the equation for Newton's second low is summation of force equals mass times acceleration short. So the equation or the forces acting on the baby would be summation was empty. So the four Cesar then showing, which is directed up board so he suborn my nose the week, which is directed downward, equals must the mass off the baby in a basket names me absolutely short. So seems here. The baby is not accelerating, so it's an equilibrium. It's address, so this is equal to zero. So this gives us he's a born equals wheat so sick and see. So in order, another way, you have to know what you can see. He's one year is equal to the 10 short, which pulls the scale down so that will give the scale. It's reading so that 10 shown our attention. One is equal to the scary reading, which is 55 new daughters. Right to be one is equal to 55 dots pants. The weight off the baby with the basket would be also equal Do 55 new guns. Now that we know the week, we can also for the mass of the baby in a basket. As we know, dill weed is equal to the gravitational force To the gravitational force is equal door mass times acceleration. But that absolutely showing is the acceleration due to gravity a constant which is equal to 9.8 meters. Three seconds. Very so the wheat she's lost the gravitational forces equals mass times G. G. So therefore, that must IHS the equation for Demas is the weak divided by the acceleration due to so um but you're saying the values the weight is 55 new doors and then he is 9.8 meters per seconds. Weird. So this really your soul dual 0.6. So answer for it at the ISS, 5.6 kilograms. This is the combined us off the basket. So for leather me for leather, me were asked Would it mean of the value Extension One? So was in part a where we've already seen were already able to establish that one is called no easy answer for letter B IHS 55 dimes. So for part C or others. You we need to do that. I mean, this time attention. Do so. Since tension to is the tension in the court that matches this key U So our FBT would like this. So we have everybody diagram would look like this. So we have here that ensures. And then since their room, uh, attach is the skill to the ceiling. So we also have here the weight off the scale. And then, of course, since the baby with the basket with babies is attached to the scale So we also have here another force weight off the be in the week of the baby with that skin. Okay, so we have 34 assists here. I longed, uh, God. So hence if we're going through, right, agree showing for this. So equation for the force is a long way. So we have be some door. So since it's directed upward my nose the week of the baby in the basket, my nose, the weight off the scale equals mass times accidentally be sure now. So since again, our system here is address or equilibrium, so this would not be equal to zero. So will be left with Isa Abdul. Then you can dance for the other, um, rooms, right, So these are do equals the weight of the baby, plus the weight off the scale. Since we know with these values, ours can Also before he saw do so the weight off being heat last. But basket, as we know from party is 55 dogs then asked for the weight off The skill the mass is given to the mass of the scale is given so we can solve for its week or so. So the weight is equal to again mass times acceleration due to gravity. So given mass off the skill is 0.500 kilogram times 9.8 meet throughs per second squared so in Put this in your guy clearly, so you will get these are do equals 60 Your daughters. Now for letter d were just asked to sketch the situations for the system used to answer each part which we already did, or which we have here actually at, uh left part of our screen and those that did one for lead. They just referred to them for questioning

Question for 65 for quite a let us rather free body diagram off the baby place basket The weight MGI is acting downwards and that tension for Stephen is acting a ports on the baby plus basket so we can write. T one is equal to m g were t one is given us 55 Newtons So this is equal to mass into X solution due to gravity 9.8. From this we will get the mosque MM equal to five point six Katie And for pardon me, let us consider the called between the spring scale and maybe in this court the tension Stephen exists and the one is equal to the weight which is 55 k g. It is 55 Newtons and for part C, we can write the forces in the string between the spring. His skill and the ceiling are Stephen downwards. Yes, the weight off the baby plus basket and the tension force he to affords so we can write 10 72 is equal to the one less m g where even is equal to 55 Newtons Yes mg where it is here M is the mass off that is bringing scale. So we will indicate it s m s. The mass off spring skill is given us 0.5 kg in 29.8. So we will get the tension forced to equal toe 60 Newton's and for party. All the everybody diagrams are already shown about the weight office. Spring scale and attention for Stephen is balancing that tension for ski too.

We have two quick everybody diagrams for the two masses. Here we have. Ah, we know M sub one being 3.5 kilograms and step to being 4.5 kilograms and applying Newton's second law. We have that chiefs of one minus T's of two minus ems of one G. This would be equaling zero and so the tension t's of one would be equaling. M someone g plus tees up to and we know that t's up to is equaling the gravitational force on the second mass. Therefore, T's of one is gonna be equaling two EMS of one plus two multiplied by G. And so for part A, we can say that T's up to quickly is M sub to G equaling 4.5 kilograms multiplied by 9.8 meters per second. Squared and T's up to is found to be 44 Newtons and four part B T's of one is given as 3.5 plus 4.5 kilograms. Multiply by 9.8 meters per second squared. This is giving us 78 Newtons and we can say for part C excuse me, uh, for part C, we can say that we have three more masses. We have m sub three. I am so before and m some five. They have all different shapes, but we're just simply representing them by this box. Going up here is T's of three. Going down here would be m sub three multiplied by g. Going down would be Tisa before going up course be Tisa before going down. I'm sub for G and going down. She survived going up here She's five and going down and some five g So we can now say that coming going from the last mass First we can say continuing on part C T C five is gonna be simply equaling m c five multiplied by G. This is gonna give us 5.5 kilograms multiplied by 9.8 meters per second squared and this is giving us 54 Newtons now. The top chord, we are told, has attention T's of three equaling 199 Newtons. This would be for party and this can support a total of 1 99 Newton's divided by 9.80 meters per second squared. This is giving us 20.3 kilograms and we know 10.3 kilograms is already accounted for in the figure. So the unknown mass in the middle and some four needs to be equaling 2 20.3 kilograms minus 10.3 kilograms giving us 10 kilograms. And so the tension in the court above it must be enough to support himself for teams of five. And this is of course, equaling 15 0.5 kilograms. And so Tisa before is found to be equaling 15.5 kilograms multiplied by 9.80 meters per second squared equaling 152 Newton's. This would be our answer for parts D inner answer for part C. That is the end of the solution. Thank you for watching.

Would be the free body diagram for the system. We have a mast up. One would be the 3.0 killer grandmaster, and massive two would be the 1.0 kilogram mass. We know that here for part a way, we're going to apply noon, second long to the x axis of each box So we can say am sub to G Ah, sign of Fada minus t would be equal to M sub two times A. I'm so rather weakens to simply say F plus t would eat Will m sub one a. Again, these two are connected. Therefore, they're gonna have the exact same acceleration. We're gonna add these two together and then solve for the acceleration of the system so we can say m sub too. Rather, the acceleration will equal and sub to G sign of data and then this would be plus F. This would be divided by m sub one plus amps up to and weaken solve. So they would be equal to one 0.0 kilograms times 9.80 meters per second squared multiplied by sine of 30 degrees and then plus 2.3 Newtons bided by the total mass of one plus three. So four points or kilograms, and we find that the acceleration here is 1.8 approximately 1.8 meters per second squared. We're going to a plug back into the first equation. Just simply could it's easier. And we can say that here, the attention force would then be equal to m someone, eh? Minus the force f. And this would be equal to 3.0 times 1.8 minus again. Ah, here it would be minus 2.3. Let's get rid of this. You don't need that parentheses there on then here we find that attention Force is going to be equal to approximately 3.1 Newtons. This would be our attention forced. This would be an acceleration of the system. So that would be those would be your two answers for part A. Now, for part B, we want to find the essentially the critical case where F has reached the max value, causing the tension here too, then vanish. So, essentially the first equation the first part of the equation, Um, in part A. We can say that then the acceleration of equal G sign of 30 degrees, and this would of course equal 4.9 meters per second squared, or simply half of 9.8. This implies that, of course, T equals zero and then that the force would simply be equal to massive one, eh? Given that the tension force has disappeared. So this would be 3.0 kilograms multiplied by 4.9 years per second squared and this is equaling 14.7 Newton's. This would be essentially the we can say critical F ah, for the tension to disappear. That is the end of the solution. Thank you for watching.

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What Is the Tension T1 in the Cord Attaching the Baby to the Scale

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